Suppose we have a circle with the equation x^2 +y^2 =25. What is the equation to the tangent to the circle at point (4,3)?

Firstly lets draw it out-Draw a line from the origin to the point. calculate the change in y over change in x =(3-0)/(4-0)=3/4Take negative reciprocal which is equal to m. Then do y-y1=m(x-x1 ) or y = mx +c to get the final answer y=-(4/3)+25/3

NM
Answered by Nayan M. Maths tutor

2915 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

a.) simplify and expand (x+3)(2x+5) b.) differentiate (x+3)(2x+5) c.) where does this function intercept the x and y axis? d.) does this function have any turning points? if so where?


Sarah asked 20 people at a tennis tournament how they travelled there. She found that 13 of them travelled by car. Estimate how many of the total 2000 people at the tournament travelled by car.


Rearrange the formula to make 'y' the subject: x = (1 - 2y)/(3 +4y)


Write 𝑥²+6𝑥+11 in the form (𝑥+a)²+b.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning