v^2 = 2w - x^2. w = 40; x = 4. Find the value of v.

Firstly, we can put the values given in the question into our equation.v2 = 2w - x2Goes to ...v2 = 2(40) - (4)2After we do the multiplication and indices, the equation looks like this.v2 = 80 - 16Do the subtraction.v2 = 64Now, to get rid of the squared sign, we have to do the opposite to both sides of the equation. We must square root both sides./v2 = /64Do the square roots.v = 8And you have your answer!

JT
Answered by Jack T. Maths tutor

2839 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

P has coordinates (3,4), Q has coordinate (a,b), a line perpendicular to PQ has equation 3x+2y=7. Find an expression for b in terms of a


How do I find the expression for the nth term in a series of numbers?


What is a product of prime factors?


Solve the simultaneous equations: 3x+4y=19, x-6y= -23.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning