v^2 = 2w - x^2. w = 40; x = 4. Find the value of v.

Firstly, we can put the values given in the question into our equation.v2 = 2w - x2Goes to ...v2 = 2(40) - (4)2After we do the multiplication and indices, the equation looks like this.v2 = 80 - 16Do the subtraction.v2 = 64Now, to get rid of the squared sign, we have to do the opposite to both sides of the equation. We must square root both sides./v2 = /64Do the square roots.v = 8And you have your answer!

Answered by Jack T. Maths tutor

2220 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Anne picks a 4-digit number. The first digit is not zero. The 4-digit number is a multiple of 5. How many different 4-digit numbers could she pick?


How do I solve simultaneous equations? eg 1) 4x = 16 - 2y and 2) 3x + y = 9


How would you solve a quadratic equation (e.g. x^2-8x+15=0)?


Expand and simplify (x-7)^2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences