Solve the quadratic equation x^2+4x+6=0
x = (-b ± √(b2 - 4ac ))/2aa=1 b=4 c=6-4 ± √(42- 4*6) = -2 ± √(42 - 12) = -4 ± √(16- 12) = -4 ± √4 = -4 ± 2x= (-4 ± 2)/2x1= -4 + 2 / 2 = -2/2 = -1x2= -4 - 2 = -6/2 = -3
TD
x = (-b ± √(b2 - 4ac ))/2aa=1 b=4 c=6-4 ± √(42- 4*6) = -2 ± √(42 - 12) = -4 ± √(16- 12) = -4 ± √4 = -4 ± 2x= (-4 ± 2)/2x1= -4 + 2 / 2 = -2/2 = -1x2= -4 - 2 = -6/2 = -3
