Solve the simultaneous equation: 3x + 2y = 4 , 4x + 5y = 17

the first thing to do when trying to solve simultaneous equations like this one is to look for a common coefficient. one of these doesn't exist in either equation therefore you have to multiply one or both of the equations to find a common coeficient. In this case you need to multiply the first equation by 5 and the second equation by 2 to find a common coefficient between the y terms. This leaves us with 15x + 10 y = 20, 8x + 10y = 34. now you must minus the second equation from the first to eliminate the y coefficients leaving us with 7x = -14. You can then see that x = -2. We can now substitute this back into either of the starting equations. 3*-2 + 2y = 4, which simplifies to 2y = 10 which shows us that y = 5. You then have the answer to the question x = -2, y = 5.

MJ
Answered by Mohammad J. Maths tutor

3104 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A square has sides of length x cm. The length of a rectangle is equal to the perimeter of this square. The perimeter of this rectangle is 14x cm. Find an expression for the width of this rectangle. Give your answer in terms of x.


How do I solve an algebraic expression when the unknown is on both sides of the equals sign?


Dominik hires a satellite phone. His total hire charge is £860. For how many weeks did he hire the phone? (Total hire charge = No. of week X 90 +50)


Solve the simultaneous equations to find the values of x and y: 3x + 5y = -4 and 10x - 4y = -34


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning