Solve simultaneously, x+y=2 and 4y^2-x^2=11

(1) x + y = 2(2) 4y2 - x2 = 11
Rearrange (1) to x= 2-y & substitute x=2-y into equation (2)
Simplify the new equation to 3y2+4y-15 = 0, use quadratic formula or simplify to (3y-5)(y+3)=0 and solve to get
y1= 5/3 y2 = -3
Substitute the values of y1 and y2 into equation one and solve for the 2 values of x
y1= 5/3 x1= 1/3 y2 = -3 x2 = 5
Substitute answers for x and y back into the original equations to verify they are correct

Answered by Nicholas N. Maths tutor

3238 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

3/5 of a number is 162. What is that number?


Solve simultaneously. x^2+y^2 = 25 ; y - 3x = 13


How to be fully prepared for the exam?


Expand and simplify 3 (y + 4) - 2 (4y + 1)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences