Find the points of intersection of the line y+x=8 and a circle with centre at (3,-2) and radius 5.

1 Circle Equation: (x-3)2+(y+2)2=52 2 Line Equation: y=-x+8Sub Equation 2 into 1(x-3)2+(10-x)2=25x2-13x+42=0(x-7)(x-6)=0x=7,x=6 Sub Values back into equation 2Points = (7,1)&(6,2)

Answered by Jamie B. Maths tutor

2140 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a.


How do you find the mean of a grouped frequency table?


Expand and Simplify: 16=(x-3)(x+3)


Solve the simultaneous equations 3x+y=16, x+y=10


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences