Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.

First we need to find the derivative of the curve:dy/dx = 8 - 4X.We can then find the X coordinate by setting this equal to zero: 0 = 8 - 4X, X = 2.Plugging this back into the original equation gives us the Y coordinate: Y = 8(2) - 2(2)2 - 9 = -1, Y = -1.Therefore the coordinates of the point are (2, -1)We know that this point must be a maximum as the coefficient of X2 is negative and therefore the curve is n shaped.

ML
Answered by Michael L. Further Mathematics tutor

2557 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

The line y = 3x-4 intersects the curve y = x^2 - a, where a is an unknown constant number. Find all possible values of a.


How to solve the inequality 1 - 2(x - 3) > 4x


The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.


The function f is given by f(x) = SQRT(2x − 5). Work out x when f(x) = 1.2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning