Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.

First we need to find the derivative of the curve:dy/dx = 8 - 4X.We can then find the X coordinate by setting this equal to zero: 0 = 8 - 4X, X = 2.Plugging this back into the original equation gives us the Y coordinate: Y = 8(2) - 2(2)2 - 9 = -1, Y = -1.Therefore the coordinates of the point are (2, -1)We know that this point must be a maximum as the coefficient of X2 is negative and therefore the curve is n shaped.

ML
Answered by Michael L. Further Mathematics tutor

2473 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Why does tanx = sinx/cosx ?


f(x) = 2x^3+6x^2-18x+1. For which values of x is f(x) an increasing function?


To differentiate a simple equation: y= 4x^3 + 7x


express z(2+i)=(1+2i)^2 in the form z=x+iy


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning