Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.

First we need to find the derivative of the curve:dy/dx = 8 - 4X.We can then find the X coordinate by setting this equal to zero: 0 = 8 - 4X, X = 2.Plugging this back into the original equation gives us the Y coordinate: Y = 8(2) - 2(2)2 - 9 = -1, Y = -1.Therefore the coordinates of the point are (2, -1)We know that this point must be a maximum as the coefficient of X2 is negative and therefore the curve is n shaped.

ML
Answered by Michael L. Further Mathematics tutor

2242 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Why does the discriminant b^2-4ac determine the number of roots of the quadratic equation ax^2+bx+c=0?


3x^3 -2x^2-147x+98=(ax-c)(bx+d)(bx-d). Find a, b, c, d if a, b, c, d are positive integers


Solve the simultaneous equations xy=2 and y=3x+5.


Let y = (4x^2 + 3)^4. Find dy/dx.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning