Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.

First we need to find the derivative of the curve:dy/dx = 8 - 4X.We can then find the X coordinate by setting this equal to zero: 0 = 8 - 4X, X = 2.Plugging this back into the original equation gives us the Y coordinate: Y = 8(2) - 2(2)2 - 9 = -1, Y = -1.Therefore the coordinates of the point are (2, -1)We know that this point must be a maximum as the coefficient of X2 is negative and therefore the curve is n shaped.

ML

Related Further Mathematics GCSE answers

All answers ▸

Use the factor theorem to show that (x-1) is a factor of x^3 - 3x^2 -13x + 15


Given that xy=2 and y=3x+5, find x and y. Do not use trial and improvement.


Find the coordinates of any stationary points of the curve y(x)=x^3-3x^2+3x+2


A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.