Find g(f(x)) where g(x)=2x+4 and f(x)=x^2+1.

With functions of functions you work from the inside out, so you substitute the function f(x) for the x in g(x). We know that f(x)=x2+1 and g(x)=2x+4. In this question you therefore replace the x in 2x+4 with x2+1. This leads to g(f(x))=2(f(x))+4, or g(f(x))=2(x2+1)+4. The next step is to expand the brackets, giving 2x2+2+4, and then to collect like terms to give g(f(x))=2x2+6.

GM
Answered by Georgina M. Maths tutor

2728 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x + 2y = 9 and x + 7y = 22.


i) Make y the subject of the expression x = ((a-y)/b))^1/2 ii) Simplify fully (2x^2 − 8)/(4x^2 − 8x)


Solve for x, 15x+8 = 53


Expand the brackets: (x + 5)(x - 3)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning