Solve the simultaneous equations 2x + y = 8 and 3x + 2y = 14

We want to make the number in front of either x or y the same in both equationsSo we multiply the first equation by 2(2x x 2) + (y x 2) = (8 x 2)4x + 2y = 16We then subtract the second equation from our new one 4x + 2y = 16-3x +2y = 14x + 0 = 2So x = 2Substitute this into either equation(2 x 2) + y = 84 + y = 8y = 8 - 4 = 4So the answer is x = 2 and y = 4

Answered by Roshene M. Maths tutor

3922 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The ratio 2 centimetres to 6 metres can be written in the form 1 : n. Find the value of n.


5x – 6 = 3x + 7


Solve the simultaneous equations: y = x + 6, x^2 + 2y = 9


Solve the simultaneous equations using the substitution method. 2y+x=8 and 1+y=2x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences