Work out the coordinates for the stationary point of y = x^2 + 3x + 4
dy/dx = 2x + 3dy/dx = 0 at stationary pointTherefore 2x + 3 = 0so x = -3/2so y = (-3/2)^2 +3 (-3/2) + 4so y = 9/4 - 9/2 + 4therefore y = 7/4so the coordinates of the stationary point are (-3/2 , 7/4)
IM
Answered by Isaac M. • Further Mathematics tutor
4476 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Given that xy=2 and y=3x+5, find x and y. Do not use trial and improvement.
Find the gradient of the line x^2 + 3x - 6 at the point (5,34)
x^3 + 2x^2 - 9x - 18 = (x^2 - a^2)(x + b) where a,b are integers. Work out the three linear factors of x^3 + 2x^2 - 9x - 18. (Note: x^3 indicates x cubed and x^2 indicates x squared).
Point A lies on the curve: y=x^2+5*x+8. The x-coordinate of A is -4. What is the equation of the normal to the curve at A?