Work out the coordinates for the stationary point of y = x^2 + 3x + 4
dy/dx = 2x + 3dy/dx = 0 at stationary pointTherefore 2x + 3 = 0so x = -3/2so y = (-3/2)^2 +3 (-3/2) + 4so y = 9/4 - 9/2 + 4therefore y = 7/4so the coordinates of the stationary point are (-3/2 , 7/4)
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