Find the tangent to the curve y=x^3+3 at the point x=1.

1. Differentiate the Equation of the curve to find the gradient: y'=3x^2

2. The gradient of the tangent is found by substituting x=1 into y'=3x^2: Gradient of tangent=3

3. Now we must find out the co-ordinates of the point. These are (x=1y=1^3+3) = (1,4).

4. Now to find out the equation of the tangent, substitute x=1, y=4 and m=3 into y=mx+c to get c=1, (the y-intercept)

5. This gives the tangential equation as y=3x+1.

SK
Answered by Sevenia K. Maths tutor

4149 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the integral of the function y = ln(x)


Solve x^3+2x^2+x=0


A small stone is projected verically upwards from a point O with a speed of 19.6ms^-1. Modeeling the stone as a particle moving freely under gravity find the time for which the stone is more than 14.6m above O


A school has 1200 pupils. 575 of these pupils are girls. 2/5 of the girls like sports. 3/5 of the boys like sport. Work out the total number of pupils in the school who like sport.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences