Solve algebraically the simultaneous equations: (x^2)+(y^2) = 25 , y-3x = 13
Step 1: First rearrange second equation for either x or y (in this example it is easier to make y the subject of the equation: y = 13+3xStep 2: Substitute the expression obtained for y into the first equation ( (x^2) + (13+3x)^2 = 25 )Step 3: Clean up the equation ( 10x^2+78x+144 = 0 )Step 4: Factorise ( (5x+24) (x+3) = 0 )Step 5: Solve for x ( x = -24/5 and -3 )Step 6: Substitute calculated values of x into the first rearranged equation of y to obtain corresponding values of y ( y = -7/5 and 4 )
SB
Related Maths GCSE answers
All answers ▸a) Find the equation of the line that passes through (2,10) and (4,16) b) Find the point where the line in (a) intersects the line y=5x-2
Prove that the square of an odd number is always 1 more than a multiple of 4.
A family go into a shop, they buy three sandwiches and two packets of crisps. It costs them £9. Another family buy five sandwiches and six packets of crisps. It costs them £19. How much does two sandwiches and five packets of crisps cost?
Solve the simultaneous equations 3x + y = 23 and 4x + 4y = 52