5(7x + 8) + 3(2x + b) ≡ ax + 13 Find the values of a and b
35x + 6x + 3b ≡ ax + 13 41x + 3b ≡ ax + 13 when x=0 3b + 40 = 13 3b= -27 b=-9 so 41x - 27 + 40 ≡ ax + 13 when x = 1 41-27 + 40 = a + 13a = 41
TM
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Solve x^2 + 7x + 10 = 0
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