Find the complex solutions for the following equation: -3x^2+4x+4=0
- -3x2+4x+4 = 0 using factorisation find the quadratic in the form (-3x+a)(x+b)=0 find two numbers (a and 3b) that have a product of 4 and a sum of 4 a =2 and 3b =2 ➔ a =2 and b =2/3 (-3x+2)(x=2/3)=0 if the product of (-3x+2) and (x=2/3) is 0 then (-3x+2)=0 or (x=2/3)=0 or both hence x = -2/3 or x = 22) Using the quadratic equation The quadratic equation ➔ ax2 + bx + c = 0 ➔ x = -b±√(b2-4ac) / 2a -3x2+4x+4 = 0 ➔ a=-3, b=4, c=4 into the equation and solve x = -4±√(42-4(-3)(4)) / 2(-3) x = -4±√(16 + 48) / -6 x = -4±√64 / -6 x = -4±8 / -6 x = 4/-6 or -12/-6 x = -2/3 or x = 2
