Show that (𝑥 − 1) is a factor of 𝑓(𝑥)=2𝑥^3 + 𝑥^2 − 8𝑥+ 5. Hence fully factorise 𝑓(𝑥) fully.

For the show that part of the question simply substitute all the 𝑥's in 𝑓(𝑥) with 1, as the factor 𝑥 − 1 means that 𝑥 - 1 = 0 therefore 𝑥 = 1. Once substituted in solve the equation and show that it is equal to 0 which proves 𝑥 − 1 is a factor of the equation.For the second part use synthetic division to factorise the equation, diving 1 into the equation (with a remainder 0) to produce a quadratic equation which then can be solved through standard factoring. The solution is 𝑓(𝑥) = (𝑥 − 1)(𝑥 + 2)(𝑥 − 1)

CB
Answered by Charlotte B. Maths tutor

2766 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

Differentiate the equation: 3x^2 + 4x + 3


If f(x) = 1/(6x^2), where x not equal to 0, find the rate of change when x=4.


Find ∫((x^2−2)(x^2+2)/x^2) dx, x≠0


Given that, dy/dx = 6x^2 - 3x + 4, and y = 14 when x = 2, express y in terms of x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning