Write 2-(x+2)/(x-3)-(x-6)/(x+3) as a single fraction of ax+b/x^2-9. What is a and b?

Multiply according terms so that the denominators are the same for all fractions. [2(x-3)(x+3)/(x-3)(x+3)]-[(x+2)(x+3)/(x-3)(x+3)]-[(x-6)(x-3)/(x-3)(x+3)]Expand out the brackets: 2x2-18-x2-5x-6-x2+9x+18/x2-9Simplify: 4x-42/x2-9 Answer: a=4 b=-42

Answered by Nicholas S. Maths tutor

8414 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The point P has coordinates (4, 5). The point Q has coordinates (a, b). A line perpendicular to PQ is given by the equation 5x+3y=11. Find an expression for b in terms of a.


v^2 = 2w - x^2. w = 40; x = 4. Find the value of v.


Solve the simultaneous equations 3x+5y=7, 2x-3y=11


f(x)=x^2+12x+32=0, solve for x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences