solve the simultaneous equation x^2 + 2y = 9 , y - x = 3

First we need to find a value for x in terms of y , this can be done by rearranging the second equation y - x = 3 to give x = y - 3. This equation is then substituted into the first equation so that everything is in terms of y giving us (y - 3)^2 + 2y = 9. We then multiply out the brackets to give us y^2 - 6y + 9 + 2y = 9 this simplifies to y^2 - 4y = 0. Therefore y = 0 to find the x value we sub this value of y into the second equation to give 0 - x = 3 and solve to find x = -3

Answered by Sara B. Maths tutor

2477 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify fully 4(x - 2) - 2(3 - 5x)


How do you know what to do first when solving composite function?


a=7 and b=2, Work out the value of (a/b)-a^b


James is 7 years older than Kate. Sam is twice as old as James. The sum of their ages is 77. Find the ratio of Kate's age to James' age to Sam's age.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences