solve the simultaneous equation x^2 + 2y = 9 , y - x = 3

First we need to find a value for x in terms of y , this can be done by rearranging the second equation y - x = 3 to give x = y - 3. This equation is then substituted into the first equation so that everything is in terms of y giving us (y - 3)^2 + 2y = 9. We then multiply out the brackets to give us y^2 - 6y + 9 + 2y = 9 this simplifies to y^2 - 4y = 0. Therefore y = 0 to find the x value we sub this value of y into the second equation to give 0 - x = 3 and solve to find x = -3

SB
Answered by Sara B. Maths tutor

2919 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Line L goes through point (2,13) and is perpendicular to the line y = 4x-5. Find the equation of line L.


Anna and Lionel share $675 in the ratio 4 : 5 Lionel gives 3 5 of his share of the money to his mother. How much money does Lionel give to his mother?


Find the solutions to the following equation x^2 - 5*x + 6 = 0


5x+3 = 18. What is the value of x?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning