Given point A: (5,9), point B: (d,15) and the gradient of line AB is 3... what is the value of d?
First use the gradient equation for a line: difference in y over difference in x:dy/dx = gradienttherefore: (15-9)/(d-5) = 315-9=3(d-5)6=3d-1521=3dtherefore d = 7
JC
Related Maths GCSE answers
All answers ▸Prove that 12 cos(30°) - 2 tan(60°) can be written as √k where k is an integer, state the value of k.
What is Pythagoras's theorem?
Quadratic Equations and factorising
If it takes 5 machines 5 minutes to make 5 widgets, how long would it take 100 machines to make 100 widgets?