A quadratic curve intersects the axes at (–3, 0), (3, 0) and (0, 18). Work out the equation of the curve

Using the equation y = ax2 + bx + cCreate 3 separate equations:-a(3)2 + b(3) + 18 = 0 -a(-3)2 + b(-3) + 18 = 0
-9a+3b = -18-9a - 3b = -18
add the equations:-9a-9a-3b+3b=-18-18-18a = -36a = 2
Substitute a into equation to find b:
-2(9) - 3b = -18b =0
Therefore,
y = -2x2 + 18

Answered by Stanley S. Maths tutor

7355 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If a cookie recipe requires 280g of flour for 12 cookies how much flour is needed to make only 9 cookies


Fully simplify the expression: 4 / (sqrt(8) + 4)


If the two shorter lengths of the triangle have sizes 4cm and 3cm, what is the length of the longest side?


Find the equation of the line perpendicular to y=2x-1 that passes through (2,0)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences