Using the parametric equations x=6*4^t-2 and y=3*(4^(-t))-2, Find the Cartesian equation of the curve in the form xy+ax+by=c
Firstly make t the subject for both equations
(x-7)/6=4^t
(y+2)/3=4^(-t)
Times them together to eliminate t
((x-7)/6)((y+2)/3) = (4^t)*(4^-t)=4^0=1
Rearrange to the form required
(x-7)(x+2)=18
xy-7y+2x-14=18
xy+2x-7y=32
AC
Related Maths A Level answers
All answers ▸express x^2-4x+9 in the form (x-q)^2+y
i) Using implicit differentiation find dy/dx for x^2 + y^2 = 4 ii) At what points is the tangent to the curve parallel to the y axis iii) Given the line y=x+c only intersects the circle once find c given that c is positive.
How do I find the nature of a stationary point
Find the set of values for which: x^2 - 3x - 18 > 0