(x+2)/(x-3) - (x-1)/(x+3) can be written in the form (ax+b)/(x^2-9). Work out the value of a and the value of b.

Recall that in order to add and subtract fractions, they must have the same denominator. Therefore, we multiply the first fraction by (x+3)/(x+3) and the second fraction by (x-3)/(x-3) to create a common denominator of (x-3)(x+3) (which is equivalent to x2-9). The next step is to expand out and simplify the numerator;(x+2)(x+3) - (x-1)(x-3) = x2+2x+3x+6 -(x2-x-3x+3) = x2+5x+6 -(x2-4x+3) = x2+5x+6-x2+4x-3=9x+3. This leaves us with the fraction as (9x+3)/(x2-9). Our final step is to identify a and b. We can see that a=9 and b=3.

Answered by Hannah P. Maths tutor

4123 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2+5x+6=0 by factorising


Complete the square for the equation x^2 - 12x + 8 = 0


The mean of 5 numbers is 42. The 5 numbers are 45,29,63,42 and X. Find the value of X.


y is inversely proportional to d^2 and when d = 10, y = 4. d is directly proportional to x^2 and when x = 2, d = 24. Find a formula for y in terms of x. Give your answer in its simplest form.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences