Solve: x^2 – x – 12 = 0

Method 1: Solve by inspection.
Demonstrate that quadratic equations can often be written in the form (x+a)(a+b) = 0. Explain that possible solutions arise as a result of either (x+a) or (x+b) =0. Note that ab = -12 , and a+b = -1 (the coefficient of the x term). Through solving these simultaneous equations or simple inspection we conclude that:a = -4, b = +3. We then substitute these values into our original form: (x+a)(a+b) = 0 , concluding that x must equal 4, -3.
Method 2: Use the quadratic formula (-b+-(√b^2-4ac) ) / 2a.
Substituting a = 1, b = -1, c= -12 we arrive at the answer x = 4,-3.

NA
Answered by Nikesh A. Maths tutor

3085 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Examine the sequence 1 + 1/3 + (1/3)^2 + … + (1/3)^n Under what condition does it converge? What does it converge to?


Jess wants to buy 30 mugs for her tea party. She can buy them at Shop A at £3.49 each or at Shop B as a pack of 30 at £58 plus VAT at 20%. She wants to get the cheapest option. Which shop should she buy from?


Using the substitution method, solve the following simultaneous equations 2y+3x=14 and 6x-y=8


A square is placed in a circle of area (49π)cm^2 such that all four vertices of the square lie on the circumference of the circle. What is the area of the square?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning