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If you have 1.33g of oxygen (Mr = 32) in a container of volume 1000cm^3 at atmospheric pressure (101.3*10^3 Pa), what is the temperature of the gas in Celsius? R=8.314

T=20.2 degrees Celsius. Start by finding number of moles using n=mass/Mr so n=1.33/32=0.0416. Find the volume in m^3 using 1cm^3=110^-6 m^3 giving V=110^-3 m^3 then rearrange PV=nRT to get T=PV/nR so T=(101.310^3 * 110^-3) / (0.0416 * 8.314)=293.2K then convert to Celsius using K-273 so 293.2-273=20.2 degrees Celsius.

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If you have 1.33g of oxygen (Mr = 32) in a container of volume 1000cm^3 at atmospheric pressure (101.3*10^3 Pa), what is the temperature of the gas in Celsius? R=8.314

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