A car of mass 1500kg is travelling at 10 ms-1 along a horizontal road. A brake force of 3000N brings it to rest. Calculate the deceleration of the car and the distance travelled by the car whilst decelerating.

To calculate the deceleration of the car we must re-arrange F=ma to make a the subject of the formula, a = F/m. We then put in the numbers to get, 3000/1500, to get a deceleration of 2 ms^-2.
To get the distance the car has travelled we need to use one of our SUVAT equations. We know initial velocity, u = 10, the final velocity, v = 0 as the car is at rest, the acceleration, a = -2, and we want to find the distance, s. We therefore select the equation with these terms in which is v^2 = u^2 + 2as. We re-arrange to make s the subject of the formula, (v^2 - u^2)/2a = s, and sub in the numbers, to get -(10^2)/2*-2 = 25m.

Related Physics A Level answers

All answers ▸

what would be the mass required to keep an object with a mass of 250kg orbiting at a constant distance of 100km with a linear velocity of 100m/s?


What is the difference between potential energy and potential?


A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.


What is the Photoelectric effect?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences