Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

5x + y = 21x - 3y = 9First, multiply the equation one by 3 so we can cancel out the y's.15x + 3y = 63 (we've now multiplied this by 3)x - 3y = 9Now we can add the two equations together, thus adding 3 and -3, cancelling the y's out.15x + x = 16x3y + (-3y) = 0y (or in other words, just 0)63 + 9 = 72So, the added equation is:16x + 0 = 72Or, in other words16x = 72Now divide each side by 16 to get x:x = 72/16 x = 4.5Now, sub the value of x back into the first of the original equations to get y:5x + y = 21(5 x 4.5) + y = 2122.5 + y = 21 (now takeaway 22.5 from both sides)y = -1.5 To check this is correct, you can sub x = 4.5 into the second original equation to get the same value of y:x - 3y = 94.5 - 3y = 9 (now takeaway 4.5 from each side)-3y = 4.5 (now times both sides by -1 to get a positive value of y)3y = -4.5 (now divide both sides by 3)y = -1.5Both these values of y are the same so the equation checks outThe final answers are:x = 4.5 y = -1.5

SP
Answered by Sebastian P. Maths tutor

3097 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If a=2 and b=3 , find the value of 2(a−b)+3(a+b)


Write x^2 - 6x +7 in the form (x+a)^2 +b


Using the quadratics formula find the two solutions to x^2 + 3x + 2 = 0.


Three points have coordinates A(-8, 6), B(4, 2) and C(-1, 7). The line through C perpendicular to AB intersects AB at the point P. Find the equations of the line AB and CP.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning