Show that the matrix A is non-singular for all real values of a

Given: A = [a -5; 2 a+4]. 1) First find the determinant of A using the known formula => det A = a2+ 4a + 10. A singular matrix is one in which it's determinant equals zero (the determinant of a matrix is a number that captures information about the characteristics of the matrix). The roots of the quadratic are complex, so the graph never equals zero/ no real roots. Therefore it must be a non-singular matrix.

Answered by Further Mathematics tutor

8377 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Show that G = {1, -1} is a group under multiplication.


Find the GS to the following 2nd ODE: d^2y/dx^2 + 3(dy/dx) + 2 = 0


Why am I learning about matrices? What are they?!


Write sin(4x) in terms of sin and cos.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning