Show that the matrix A is non-singular for all real values of a

Given: A = [a -5; 2 a+4]. 1) First find the determinant of A using the known formula => det A = a2+ 4a + 10. A singular matrix is one in which it's determinant equals zero (the determinant of a matrix is a number that captures information about the characteristics of the matrix). The roots of the quadratic are complex, so the graph never equals zero/ no real roots. Therefore it must be a non-singular matrix.

Answered by Further Mathematics tutor

9451 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Evaluate ∫sin⁴(x) dx by expressing sin⁴(x) in terms of multiple angles


Express the complex number (1+i)/(1-i) in the form x+iy


Prove that 27(23^n)+17(10^2n)+22n is divisible by 11 for n belongs to the natural numbers


A curve C has equation y = x^2 − 2x − 24 x^(1/2), x > 0. Find dy/dx and d^2y/dx^2. Verify that C has a stationary point when x = 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning