The variables we are given are mass (m), time (t), temperate CHANGE (delta T) and SHC (c) and we are asked for energy. Think of the equations for energy we know: mgh, 1/2mv2, mcdeltaT...the first two energy equations are not relevant to this situationThe equation needed is Q = m x c x deltaTdelta T is the change in temperature. Water cools from boiling therefore: 100-deltaT = 83----> delta T = 17Q = 0.6 x 4200 x 17 = 42840 J