Differentate sin(x^2+1) with respect to x

y = sin(x2+1) In general, the chain rule is: dy/dx = f(g(x)) = df/dg * dg/dx Applying this to y: dy/dx = d(sin(x2+1))/d(x2+1) * d(x2+1)/dx = cos(x2+1) * (2x) = 2xcos(x2+1)

Related Maths A Level answers

All answers ▸

What are logarithms and how do you manipulate them?


Find the area under the curve of y=x^2 between the values of x as 1 and 3


Given that: 2tanθsinθ = 4 - 3cosθ , show that: 0 = cos²θ - 4cosθ + 2 .


Find the inverse of f(x) = (3x - 6)/2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences