Solve the simultaneous equations 5x + 3y = 24 and 3x - 4y = 26

Ok, so here are the equations5x+3y=243x-4y=26So let's multiply the first equation by 3, which gives us:15x+9y=72Now let's multiply the second equation by 5, which gives us:15x-20y=130So we're now left with:15x+9y=7215x-20y=130Let's rearrange both of these equations to make 15x the subject. So now we're left with:15x = 72-9y15x= 130+20yNow we can compare these two equations, to give us:72-9y=130+20y (=15x)If we rearrange this new equation, we find that:20y + 9y = 72 - 13029y = -58y = -2Since we now have a value for y, we can substitute this back into 5x + 3y = 245x + 3(-2) = 245x -6 = 245x = 30x = 6So, are final answer is x = 6 and y = -2

WS
Answered by William S. Maths tutor

11694 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the quadratic 2x^2+7x+6 by completing the square


Make d the subject of the formula: 3d + dxy = 4


4x^2 + 8x + 3 can be written in the form a(x + b)^2 + c where a, b and c are whole numbers. Work out the values of a, b and c.


Work out the value of (√12 + √3) squared. Assume square roots are positive.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning