If a 10N tension force is exerted on a steel beam (E = 200 GPa) with cross-sectional area 1cm^2, what is the stress acting on the beam? What is the change in length of the beam, if the beam is 10cm long?

F = 10NA = 1x10^-6 m^2Therefore, Stress = 10 MPaStrain = Stress / E = 10 / 200 x10^3 = 5x10^-5 delta L = strain x length = 5x10^-4 cm = 5 micrometers

Answered by Elliott M. Physics tutor

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