√ (6²+8²) = ∛(125a³) Find a.

6²= 36 8²=6436+64=100√ 100 =10Therefore, 100=∛(125a³)∛(125a³) =∛125 X ∛a³=5 X a =5aSo, 10=5aa=2

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simplify (x-1)^2 - (x-1)


For which values of x is x^2 - 5x + 6 < 0 true?


solve: x^2= 4(x-3)^2


(6^2 + 8^2)^1/2 = (125a^3)^1/3 Work out the value of a?


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