Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2

dy/dx = 3x2 - 8x - 3
when dy/dx = 0 , 0 = 3x2 - 8x - 3
Factorise : 0= (3x + 1)(x - 3)
when 3x+1 =0 , x = -1/3when x-3=0 , x =3
so x = -1/3 , 3co-ordinates are : (-1/3, 68/27), (3, -16)

Answered by Mahir C. Maths tutor

5169 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

On the same diagram, sketch the graphs of: y = |5x -2| and y = |2x| and hence solve the equation |5x - 2| = |2x|


The polynomial p(x) is given: p(x)=x^3+2x^2-5x-6, express p(x) as the product of three linear factors


How do I find the stationary points of a curve?


Differentiate with respect to x: y = xln[2x]


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences