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Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2

dy/dx = 3x² - 8x - 3
when dy/dx = 0 , 0 = 3x² - 8x - 3
Factorise : 0= (3x + 1)(x - 3)
when 3x+1 =0 , x = -1/3when x-3=0 , x =3
so x = -1/3 , 3co-ordinates are : (-1/3, 68/27), (3, -16)

Answered by Mahir C. • Maths tutor

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