Explain why the first ionisation energy of sulphur is lower than that of phosphorus.

The general trend is that the first ionisation energies increases across the period from Na to Ar. But the first ionisation energy of sulphur is lower than phosphorus because the electronic configuration is less stable. Like when you get on the bus, you would sit on whatever seat you can where you don’t have to sit next to someone until all of the free two-seats are used up. The same is with electrons - they fit into the orbitals one at a time until the only orbitals available are ones with electrons already in them. There is extra repulsion between electrons when two fit into the same orbital. The electronic configuration of phosphorus (3p3) means the electrons are in a 'maximum unpairing' configuration, which is very stable. The extra electron of sulphur (3p4) is added to an orbital which already contains an electron and the repulsion between these two electrons makes it easier to remove this electron and therefore the first ionisation energy is lower.

Answered by Lana R. Chemistry tutor

11463 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

In order to find the [H+] ion content of H2SO4 (Sulphuric Acid), why must you divide by two after using the formula for pH calculation?


Unsaturated fats change bromine water from orange to colourless. How?


An amino acid contains 52.2% carbon, 9.3% hydrogen, 8.7% nitrogen and 29.8% oxygen by mass and has a relative molecular mass of 161 g/mol. What is its molecular formula? What functional groups must it have?


An alcohol, X has an Mr of 74 and percentage composition of 64.9% Carbon, 13.5% Hydrogen and 21.6% Oxygen. It does not turn potassium dichromate (VI) green. Determine the structural formula of X, and state its name.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences