A child weighing 50kg is pushed down a 2m long slide (u=0.1), angled at 45 degrees from the horizontal, at 5m/s. At what speed does the child reach the bottom of the slide?

Change in GPE=Change in KE + ResistanceResistance = ForcexDistnaceForce=Friction= R u = masscos45g2 * 0.1Change in KE = 0.5m*(v2-25)Change in GPE = mg2Sin 45Can cancel down by m (both sides in all parts)9.81.414=0.5(v^2-25)+0.14149.82(9.81.414 -0.14149.8)=(v2-25)v2= 49.94v=7.06 m/s

Related Further Mathematics A Level answers

All answers ▸

Can you show me how to solve first order differential equations using the integrating factor method?


Compute the derivative of arcsin(x).


Find, without using a calculator, integral of 1/sqrt(15+2x-x^2) dx, between 3 and 5, giving your answer as a multiple of pi


How do you prove the formula for the sum of n terms of an arithmetic progression?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences