Answers>Further Mathematics>A Level>Article

A child weighing 50kg is pushed down a 2m long slide (u=0.1), angled at 45 degrees from the horizontal, at 5m/s. At what speed does the child reach the bottom of the slide?

Change in GPE=Change in KE + ResistanceResistance = ForcexDistnaceForce=Friction= R u = masscos45g2 * 0.1Change in KE = 0.5m*(v²-25)Change in GPE = mg2Sin 45Can cancel down by m (both sides in all parts)9.81.414=0.5(v^2-25)+0.14149.82(9.81.414 -0.14149.8)=(v²-25)v²= 49.94v=7.06 m/s

Answered by Matthew W. • Further Mathematics tutor

2930 Views

A child weighing 50kg is pushed down a 2m long slide (u=0.1), angled at 45 degrees from the horizontal, at 5m/s. At what speed does the child reach the bottom of the slide?

Related Further Mathematics A Level answers

Prove that 1+4+9+...+n^2 = n(n+1)(2n+1)/6.

What IS a Taylor Series?

How do i figure out if integrals are improper or not and how do i know which limit is undefined?

A rectangular hyperbola has parametric equations x = 4t, y = 4/t , (z non 0). Points P and Q on this hyperbola have parameters t = 1/4 and t = 2. Find the equation of the line l which passes through the origin and is perpendicular to the line PQ.