Find the area between the curve y = 8 + 2x - x^2 and the line y = 8 - 2x.
First sketch the curve and the line, noting down where they intersect each axis.area under y = 8 + 2x - x2 is given by the integral between 0 and 4 of (8 + 2x - x2) dx.area under line is given by the integral between 0 and 4 of (8-2x) dx. It's easier to do this than using the formula for area of a triangle!!So total area:area = integral between 0 and 4 of (8 + 2x - x2) dx - integral between 0 and 4 of (8-2x) dxarea = integral between 0 and 4 of (8 + 2x - x2 - (8-2x))dx Note we can combine the two integrals!!area = integral between 0 and 4 of (4x - x2) dxarea = [2x2 - x3/3]40 = 32/3
Related Maths A Level answers
All answers ▸What is the chain rule?
Given that the increase in the volume of a cube is given by dV/dt = t^3 + 5 (cm^3/s). The volume of the cube is initially at 5 cm^3. Find the volume of the cube at time t = 4.
Differentiate y = (3x^3+2x+7)/x^(1/2)
Solve the quadratic inequality: x^2 - 5x + 4 < 0