Find the equation of the line that passes through (2, 4) and (7, -11)

Step 1) Write out the general equation of a straight line: y = mx + c where m is the gradient and c is where the line intersects the y-axis. Step 2) Find the gradient: m = change in y / change in x, m = (-11-4) / (7-2), m = -15 / 5 m = -3 Step 3) Find c: This can be done by substituting in co-ordinates of either of the points that the line passes through into the equation y = -3x + c, 4 = -3*2 + c, c = 10 Step 4) Write out the equation: y = -3x + 10

RG
Answered by Romily G. Maths tutor

3839 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

N = 2a + b. a is a 2 digit square number, b is a 2 digit cube number. What is the smallest possible value of N?


Factorise y^2 - y - 12


Expand and simplify (x-4)(2x+3y)^2


Solve the equation ((2x+3)/(x-4))-((2x-8)/(2x+1))=1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning