Find the equation of the line that passes through (2, 4) and (7, -11)

Step 1) Write out the general equation of a straight line: y = mx + c where m is the gradient and c is where the line intersects the y-axis. Step 2) Find the gradient: m = change in y / change in x, m = (-11-4) / (7-2), m = -15 / 5 m = -3 Step 3) Find c: This can be done by substituting in co-ordinates of either of the points that the line passes through into the equation y = -3x + c, 4 = -3*2 + c, c = 10 Step 4) Write out the equation: y = -3x + 10

RG
Answered by Romily G. Maths tutor

3837 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

how do i calcualte the length of an unknown side of a right angled triangle


A linear equation has terms: a+2b, a + 6b, a + 10b, ......., ........ the second term equals 8 and the fifth term equals 44. Work out the value of a & b


Solve algebraically: 6a + b = 16 ..... 5a - 2b = 19


If a right-angled triangle has one side measuring 8cm and another measuring 15cm, what is the length of the hypotenuse?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning