Solve these two equations simultaneously: 7x+y=1 and 2x^2 - y=3

Number Equations7x+y=12x^2 - y=3Rearrange equation 1 to equal yy=1-7xSubstitute 1 into 22x²- (1-7x)=32x²+7x-1=3Format into quadratic equation2x²+7x-4=0 (2x-1)(x+4)=02x-1=0 x+4=02x=1 x=1/2 x=-4Then work out the values for y by substituting the two x values into one of the original equations7x+y=17(1/2)+y=1 y=-2.57(-4)+y=1 y=-27