If angle = 50 degrees, hypotenuse = x, adjacent side = 5 cm, opposite side = 7 cm, and is a right angled triangle,Use cos(theta)=adjacent/hypotenuseSo, cos(50) = 5/xrearranging the equation to make x the subject you must times both sides by xxcos(50) = 5x/xxcos(50) = 5Now you must divide both sides by cos(50):(xcos(50))/cos(50) = 5/cos(50)x = 5/cos(50)Now type this in the calculator and you should get:x = 5.2 to one decimal place