A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.
Using the equation V2 = U2 + 2as, where V = final velocity, U = initial velocity, a = acceleration, s = displacement, we can substitute in the values given in the question to calculate the final velocity.U = 0 m/s as dropped from resta = 10m/s2s = 2 metresRearranging to solve for V gives:V = sqrt (U2 + 2as) Substituting in values:V = sqrt( 02 + 2102) V = 6.32m/s
PB
Related Physics A Level answers
All answers ▸Explain why the pressure exerted by a gas increases as they are heated at constant volume, with references to the kinetic theory of gases.
How to determine the total time of flight for a projectile launched at an angle theta to the horizontal with an initial speed u?
What is electromotive force (emf) and how can the emf of a battery be measured?
A car of mass M and a maximum power output of P is on an rough inclined plane Θ to the horizontal. What is the maximum velocity (v). Coefficient of friction=μ and air resistance=kv where k is constant