A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.
Using the equation V2 = U2 + 2as, where V = final velocity, U = initial velocity, a = acceleration, s = displacement, we can substitute in the values given in the question to calculate the final velocity.U = 0 m/s as dropped from resta = 10m/s2s = 2 metresRearranging to solve for V gives:V = sqrt (U2 + 2as) Substituting in values:V = sqrt( 02 + 2102) V = 6.32m/s
PB
Related Physics A Level answers
All answers ▸Explain what is meant by the mass defect of an atomic nucleui
On the line of centres between the Earth and the Moon, there is a point where the net gravitational force is zero. Given that the distance between the two is 385,000 km, and that the Earth has a mass 81x that of the Moon, how far is this point from Earth?
What conditions are required for simple harmonic motion?
why is gravitational potential negative?