A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.
Using the equation V2 = U2 + 2as, where V = final velocity, U = initial velocity, a = acceleration, s = displacement, we can substitute in the values given in the question to calculate the final velocity.U = 0 m/s as dropped from resta = 10m/s2s = 2 metresRearranging to solve for V gives:V = sqrt (U2 + 2as) Substituting in values:V = sqrt( 02 + 2102) V = 6.32m/s
PB
Related Physics A Level answers
All answers ▸What is the main evidence for the Big Bang theory?
A spacecraft called Deep Space 1, mass 486 kg, uses an “ion-drive” engine which expels 0.13 kg of xenon propellant each day at 30kms^-1. What is the initial increase in speed of the spacecraft
Describe how the strong nuclear force between two nucleons varies with the separation of the nucleons, quoting suitable values for separation.
In terms of the photoelectric effect, what is the work function of a material?