A ball is dropped from rest at a height of 2 metres. Assuming acceleration due to gravity (g) is 10m/s^2 calculate the velocity of the ball just before it hits the floor.
Using the equation V2 = U2 + 2as, where V = final velocity, U = initial velocity, a = acceleration, s = displacement, we can substitute in the values given in the question to calculate the final velocity.U = 0 m/s as dropped from resta = 10m/s2s = 2 metresRearranging to solve for V gives:V = sqrt (U2 + 2as) Substituting in values:V = sqrt( 02 + 2102) V = 6.32m/s
PB
Related Physics A Level answers
All answers ▸What is Newton's Third Law and what is an example of it?
A) Draw field lines around a positive point particle. B) How does a faraday cage prevent the people within it recieving a electric shock ?
Two balls of mass 3kg and 7 kg respectively move towards one another with speeds 5ms^-1 and 2ms^-1 respectively on a smooth table. If they collide and join, what velocity do they move off with?
What are the similarities and differences between an elastic and an inelastic collision?