A ladder of length 5 m is place with the foot 2.2 m from the base of a vertical wall. How high up the wall does the ladder reach?

Drawing a diagram will help to visualise the problem and realise it is based on Pythagoras's theorem: a^2 + b^2 = c^2. We have been given 'c' the hypotenuse (5 m) and one of the shorter sides (2.2 m), which we shall say is 'b' leaving one unknown side (a).
We therefore need to rearrange the equation to make 'a' the subject: c^2 - b^2 = a^2. Now substitute in the numbers: 25-2.2 = a^220.16 = a^2. So 'a' is the square root of 20.16, which gives 4.49.
Don't forget the units! So the answer is the ladder will reach 4.49 m up the wall :)

Answered by Gagandeep S. Maths tutor

3220 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

solve the following simultaneous equations 4x + 6y = 16 and x + 2y = 5


work out: ( 4 × 10^3 )^2 + 3.5 × 10^7 and give your answer in standard form.


Two simultaneous questions are given as 3x+2y = 9, and x-2y = -5. Find the values for x and y


Express 0.545454... as a fraction in its simplest form.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences