Differentiate the following: y=(7x^2+2)sinx

Differentiate using the product rule.Product rule: for y=uv , where u and v are functions of x, dy/dx=vdu/dx + udv/dxy=(7x2+2)sinx so u=(7x2+2) and v=sinx . By differentiating these functions:du/dx=14x and dv/dx=cosxnow we have expressions for u, v, du/dx and dv/dx, we can find dy/dx.Recall dy/dx=vdu/dx + udv/dx, by substituting our expressions:dy/dx=14xsinx +(7x2+2)cosx

Related Maths A Level answers

All answers ▸

Find the area under the curve of y=1/(3x-2)^0.5 between the limits x=1 and x=2 and the line y=0


How do you prove two straight lines intersect?


What is the smallest possible value of the integral ∫(x-a)^2 dx between 0 and 1 as a varies?


When I try to integrate by parts, I end up in an infinite loop. Why is this, and how do you stop?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences