What is the easiest way to expand quadratic equations?

There are many methods of expanding quadratic equations, however there is one method which I find to be far easier than the others. This method is called the "box method", and allows this to be done quickly and reliably!Here is an example. Take this example question : Expand the quadratic equation ( x + 2 ) * ( x + 3 ). First, you must draw a box divided into 4 quarters, as shown: ||||||Then, you need to place one of the brackets on the top and on the left side of this box, as below:   x________3x |a|b|2 |_c|_d|Then all you need to do is muliply the number or variable on the top of the box, and on the side of the box. Box A therefore is : x * x = x2Box B therefore is 3 * x = 3xBox C therefore is 2 * x = 2xBox C therefore is 3 * 2 = 6Then just add up all of the results and simplify : x2 + 3x + 2x + 6 = x+ 5x + 6This method also works if you have more than two figures in each bracket, so if you get asked to expand the following, you simply follow the steps again!Expand (x+ 4x+ 5x + 7) * (x + 2) First, you must draw a rectangle of two boxes in height, but simply make it longer!  ____x3_4x25x 7x |a|___b|___c|_d||e|_____f ____|___g|_h|Then follow the same steps again, multiplying one side of the box by the otherBox A : x3 * x = x4Box B : 4x2 * x = 4x3Box C : x * 5x = 5x2Box D : 7 * x = 7xBox E : 2 * x3 = 2x3Box F : 4x2 * 2 = 8x2Box G : 2 * 5x = 10xBox H : 2 * 7 = 14Add them all up to get : x4 + 4x3 + 2x+ 5x+ 8x+ 7x +10x +14 = x+ 6x+ 13x+ 17x +14. And there you go! The easiest and quickest way to expand a quadratic equation!

Answered by Alexander C. Maths tutor

12678 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find x when 2x-3=5


Solve the simultaneous equation: y=x^2+2x-2 y=4x+6


If a rectangle has area 48cm2 and sides length 6cm and (3x+2)cm, what is the value of x?


X^2 - 4y = -8 y=3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences