Solve the simultaneous equations algebraically: y = x+19 AND y = x^2 + 4x +1.

We have one linear and one quadratic equation here. Since we have a quadratic, we will have two sets of solutions. Let's solve by substitution. Substitute equation (1) into equation (2), which yields:x + 19 = x^2+4x+1OR 0 = x^2 + 3x - 18To solve this quadratic to find our x values we must first factorise, which gives:0 = (x+6)(x-3)It must follow that:x = -6 OR x = 3.Sub these two distinct real solutions into equation 1, we will get our corresponding y value:x = -6, y = 13 OR x=3, y=22.

Answered by Liam D. Maths tutor

3012 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve a quadratic equation?


One of the teachers at a school is chosen at random. The probability that this teacher is female is 3/5. There are 36 male teachers at the school. Work out the total number of teachers at the school.


Solve the equation 10x + 4 = 12x + 2


Work out 2 and 3/4 x 1 and 5/7 Give your answer as a mixed number in its simplest form.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences