Tony buys 12 apples and 7 pears for £10.90. An apple costs 20p less than a pear. What would be the cost of 4 apple and 9 pears?

Let's call an apple 'a', and a pear 'p'.If Tony bought 12 apples and 7 pears for £10.90, then we can write the following equation:12a + 7p = 10.9If an apple costs 20p less than a pear, we can say:a = p - 0.2Treating these as simultaneous equations, we can use the second equation to replace 'a' in the first equation with 'p - 0.2':12(p - 0.2) + 7p = 10.9This can be simplified:12p - 2.4 + 7p = 10.919p = 13.3p = 0.7Putting this value back into the second equation, we get:a = 0.7 - 0.2which simplifies to:a = 0.5So, an apple costs 50p and a pear costs 70p.Now, to find the cost of 4 apples and 9 pears:4 x 0.5 + 9 x 0.7 = 8.3So the cost is £8.30.

RJ
Answered by Rupert J. Maths tutor

4412 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equation: 2x + y = 18 and x−y=6


(3x+9) (7x+5)


What is standard deviation and how does it work for non-grouped data?


solve this simultaneous equation: 2x + 3y = 19 (Eq1) and 3x + y = 11 (Eq2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning