Differentiate y = 3x^4 + 6x^3

There are two really simple steps we can use to be able to differentiate in a question like this. The first step is to multiply the number in the power by the number in front of the variable - in this case the 'x'. Looking at the first term we would multiply the '4' (in the power) by the '3' (in front of the x) to get 12. The second step is to subtract one from the number in the power to get the new power. So again, looking at the first term, we would subtract 1 from '4' to get the new power which is 3. Therefore, differentiating the first term gives us 12x3. We can then repeat these two steps for the next term in the equation (6x3) to give us 18x2. We use the notation dy/dx to indicate that we have differentiated the equation so our final answer is dy/dx = 12x3 + 18x2

AB
Answered by Amrita B. Maths tutor

5093 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

s^2 - 2s - 24 = 0


How do I skecth a grpah of y = x^2 - 7x + 10?


A t-shirt is in two shops, both of which has it on sale. In shop A, the t-shirt originally cost £15, but has been reduced by 30%. In shop B, it used to cost £17 and has been reduced by 40%. In which shop is the t-shirt now cheaper, and by how much?


Make d the subject of the formula: 3d + dxy = 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning