To solve Inx + In3 = In6 we must follow some basic log rules, logb(mn) = logb(m) + logb(n)if we compare this with the left side of our equation, Inx + In3, we will set m = x and n = 3, mn is therefore 3xthis means that Inx + In3 is equivalent to In3xSo replacing that into our original equation:In3x = In6Take In of both sides3x = 6therefore x = 2